Final Answer
Step-by-step Solution
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Apply the product rule for differentiation: $(f\cdot g)'=f'\cdot g+f\cdot g'$, where $f=a+b-c$ and $g=a+b+c$
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$\frac{d}{db}\left(a+b-c\right)\left(a+b+c\right)+\left(a+b-c\right)\frac{d}{db}\left(a+b+c\right)$
Learn how to solve differential calculus problems step by step online. Find the derivative of (a+b-c)(a+bc). Apply the product rule for differentiation: (f\cdot g)'=f'\cdot g+f\cdot g', where f=a+b-c and g=a+b+c. The derivative of a sum of two or more functions is the sum of the derivatives of each function. The derivative of a sum of two or more functions is the sum of the derivatives of each function. The derivative of the constant function (-c) is equal to zero.