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Factor by completing the square $\sqrt[3]{8xy}\sqrt[3]{2y^2}$

Step-by-step Solution

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Final answer to the problem

$2\sqrt[3]{2}\sqrt[3]{x}y$
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Step-by-step Solution

How should I solve this problem?

  • Factor by completing the square
  • Integrate by partial fractions
  • Product of Binomials with Common Term
  • FOIL Method
  • Integrate by substitution
  • Integrate by parts
  • Integrate using tabular integration
  • Integrate by trigonometric substitution
  • Weierstrass Substitution
  • Prove from LHS (left-hand side)
  • Load more...
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1

The power of a product is equal to the product of it's factors raised to the same power

$2\sqrt[3]{x}\sqrt[3]{y}\sqrt[3]{2}\sqrt[3]{y^2}$

Learn how to solve product rule of differentiation problems step by step online.

$2\sqrt[3]{x}\sqrt[3]{y}\sqrt[3]{2}\sqrt[3]{y^2}$

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Learn how to solve product rule of differentiation problems step by step online. Factor by completing the square (8xy)^1/3(2y^2)^1/3. The power of a product is equal to the product of it's factors raised to the same power. The power of a product is equal to the product of it's factors raised to the same power. . Calculate the power \sqrt[3]{8}.

Final answer to the problem

$2\sqrt[3]{2}\sqrt[3]{x}y$

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Function Plot

Plotting: $2\sqrt[3]{2}\sqrt[3]{x}y$

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5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Product Rule of differentiation

The product rule is a formula used to find the derivatives of products of two or more functions. It may be stated as $(f\cdot g)'=f'\cdot g+f\cdot g'$

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