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Solve the quadratic equation $\left(5x-4\right)^2-\left(3x+5\right)\left(2x-1\right)=20x\left(x-2\right)+27$

Step-by-step Solution

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Final Answer

$x=-1,\:x=-6$
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Step-by-step Solution

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Simplify the product $-(3x+5)$

$\left(5x-4\right)^2+\left(-3x-5\right)\left(2x-1\right)=20x\left(x-2\right)+27$

Learn how to solve trigonometric integrals problems step by step online.

$\left(5x-4\right)^2+\left(-3x-5\right)\left(2x-1\right)=20x\left(x-2\right)+27$

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Learn how to solve trigonometric integrals problems step by step online. Solve the quadratic equation (5x-4)^2-(3x+5)(2x-1)=20x(x-2)+27. Simplify the product -(3x+5). Move everything to the left hand side of the equation. Expand \left(5x-4\right)^2. Subtract the values 16 and -27.

Final Answer

$x=-1,\:x=-6$

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Solve for xFind the rootsSolve by completing the squareSolve by quadratic formula (general formula)Find break even pointsFind the discriminant

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Function Plot

Plotting: $\left(5x-4\right)^2-\left(3x+5\right)\left(2x-1\right)-20x\left(x-2\right)-27$

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Answer Assistant

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1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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Main Topic: Trigonometric Integrals

Integrals that contain trigonometric functions and their powers.

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