Final Answer
$\frac{x\left(\cos\left(10x\right)+\cos\left(2x\right)\right)}{2}+C_0$
Got another answer? Verify it here!
Step-by-step Solution
Problem to solve:
$\int\cos\left(4x\right)\cos\left(6x\right)dx$
Specify the solving method
1
Rewrite the trigonometric expression $\cos\left(4x\right)\cos\left(6x\right)$ inside the integral
$\int\frac{\cos\left(10x\right)+\cos\left(-2x\right)}{2}dx$
2
As the integral that we are solving is an indefinite integral, when we finish integrating we must add the constant of integration $C$
$\frac{x\left(\cos\left(10x\right)+\cos\left(2x\right)\right)}{2}+C_0$
Final Answer
$\frac{x\left(\cos\left(10x\right)+\cos\left(2x\right)\right)}{2}+C_0$