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The sum of two terms multiplied by their difference is equal to the square of the first term minus the square of the second term. In other words: $(a+b)(a-b)=a^2-b^2$.
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$1-\cos\left(c\right)^2=\sin\left(d\right)^2$
Learn how to solve differential calculus problems step by step online. Prove that (1+cos(c))(1-cos(c))=sin(d)^2 is not an identity. The sum of two terms multiplied by their difference is equal to the square of the first term minus the square of the second term. In other words: (a+b)(a-b)=a^2-b^2.. Apply the trigonometric identity: 1-\cos\left(\theta \right)^2=\sin\left(\theta \right)^2, where x=c. There is no identity or mathematical rule that allows us to proceed trying to match both sides of the equality, so we conclude that it is not true.