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$\int\left(\left(\frac{y^3}{2}\right)^2+2\left(\frac{y^3}{2}\right)^2\left(\frac{1}{2y^3}\right)^2+\left(\frac{1}{2y^3}\right)^2\right)dy$
Learn how to solve integral calculus problems step by step online. Find the integral of ((y^3)/2)^2+2((y^3)/2)^2(1/(2y^3))^2(1/(2y^3))^2. Find the integral. Simplify the expression inside the integral. The integral \int\frac{y^{6}}{4}dy results in: \frac{1}{28}y^{7}. The integral \int\frac{1}{8}dy results in: \frac{1}{8}y.