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Factor the sum or difference of cubes using the formula: $a^3\pm b^3 = (a\pm b)(a^2\mp ab+b^2)$
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$\frac{\left(\left(64a^3\right)^{\frac{1}{3}}+343^{\frac{1}{3}}\right)\left(\left(64a^3\right)^{\frac{2}{3}}- 343^{\frac{1}{3}}\left(64a^3\right)^{\frac{1}{3}}+343^{\frac{2}{3}}\right)}{4a+7}$
Learn how to solve trigonometric integrals problems step by step online. Simplify the expression (64a^3+343)/(4a+7). Factor the sum or difference of cubes using the formula: a^3\pm b^3 = (a\pm b)(a^2\mp ab+b^2). Divide 1 by 3. Divide 1 by 3. Divide 2 by 3.