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Factor the difference of squares $36-x^2$ as the product of two conjugated binomials
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$\int_{0}^{3}\frac{x}{\left(6+x\right)\left(6-x\right)}dx$
Learn how to solve definite integrals problems step by step online. Integrate the function x/(36-x^2) from 0 to 3. Factor the difference of squares 36-x^2 as the product of two conjugated binomials. Rewrite the fraction \frac{x}{\left(6+x\right)\left(6-x\right)} in 2 simpler fractions using partial fraction decomposition. Find the values for the unknown coefficients: A, B. The first step is to multiply both sides of the equation from the previous step by \left(6+x\right)\left(6-x\right). Multiplying polynomials.