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Expand the fraction $\frac{x-3}{2x-3}$ into $2$ simpler fractions with common denominator $2x-3$
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$\int_{0}^{2}\left(\frac{x}{2x-3}+\frac{-3}{2x-3}\right)dx$
Learn how to solve definite integrals problems step by step online. Integrate the function (x-3)/(2x-3) from 0 to 2. Expand the fraction \frac{x-3}{2x-3} into 2 simpler fractions with common denominator 2x-3. Expand the integral \int_{0}^{2}\left(\frac{x}{2x-3}+\frac{-3}{2x-3}\right)dx into 2 integrals using the sum rule for integrals, to then solve each integral separately. Rewrite the fraction \frac{x}{2x-3} inside the integral as the product of two functions: x\frac{1}{2x-3}. We can solve the integral \int x\frac{1}{2x-3}dx by applying integration by parts method to calculate the integral of the product of two functions, using the following formula.