Final Answer
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Expand the fraction $\frac{x-3}{2x-3}$ into $2$ simpler fractions with common denominator $2x-3$
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$\int_{0}^{2}\left(\frac{x}{2x-3}+\frac{-3}{2x-3}\right)dx$
Learn how to solve definite integrals problems step by step online. Integrate the function (x-3)/(2x-3) from 0 to 2. Expand the fraction \frac{x-3}{2x-3} into 2 simpler fractions with common denominator 2x-3. Expand the integral \int_{0}^{2}\left(\frac{x}{2x-3}+\frac{-3}{2x-3}\right)dx into 2 integrals using the sum rule for integrals, to then solve each integral separately. We can solve the integral \int_{0}^{2}\frac{x}{2x-3}dx by applying integration by substitution method (also called U-Substitution). First, we must identify a section within the integral with a new variable (let's call it u), which when substituted makes the integral easier. We see that 2x-3 it's a good candidate for substitution. Let's define a variable u and assign it to the choosen part. Now, in order to rewrite dx in terms of du, we need to find the derivative of u. We need to calculate du, we can do that by deriving the equation above.