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Expand the integral $\int_{-3}^{-1}\left(\frac{1}{x^2}+\frac{-1}{x^3}\right)dx$ into $2$ integrals using the sum rule for integrals, to then solve each integral separately
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$\int_{-3}^{-1}\frac{1}{x^2}dx+\int_{-3}^{-1}\frac{-1}{x^3}dx$
Learn how to solve differential equations problems step by step online. Integrate the function 1/(x^2)+-1/(x^3) from -3 to -1. Expand the integral \int_{-3}^{-1}\left(\frac{1}{x^2}+\frac{-1}{x^3}\right)dx into 2 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int_{-3}^{-1}\frac{1}{x^2}dx results in: \frac{2}{3}. The integral \int_{-3}^{-1}\frac{-1}{x^3}dx results in: \frac{4}{9}. Gather the results of all integrals.