Solve the differential equation $\frac{dy}{dx}=e^{\left(3x+2y\right)}$

We can solve the integral $\int\frac{1}{e^{2y}}dy$ by applying integration by substitution method (also called U-Substitution). First, we must identify a section within the integral with a new variable (let's call it $u$), which when substituted makes the integral easier. We see that $2y$ it's a good candidate for substitution. Let's define a variable $u$ and assign it to the choosen part

Now, in order to rewrite $dy$ in terms of $du$, we need to find the derivative of $u$. We need to calculate $du$, we can do that by deriving the equation above

Isolate $dy$ in the previous equation

Substituting $u$ and $dy$ in the integral and simplify

Apply the formula: $\int\frac{1}{e^x}dx$$=-\frac{1}{e^x}$, where $x=u$

Simplify $-\frac{1}{2}\left(\frac{1}{e^u}\right)$

Replace $u$ with the value that we assigned to it in the beginning: $2y$

We can solve the integral $\int e^{3x}dx$ by applying integration by substitution method (also called U-Substitution). First, we must identify a section within the integral with a new variable (let's call it $u$), which when substituted makes the integral easier. We see that $3x$ it's a good candidate for substitution. Let's define a variable $u$ and assign it to the choosen part

Now, in order to rewrite $dx$ in terms of $du$, we need to find the derivative of $u$. We need to calculate $du$, we can do that by deriving the equation above

Isolate $dx$ in the previous equation

Substituting $u$ and $dx$ in the integral and simplify

Take the constant $\frac{1}{3}$ out of the integral

The integral of the exponential function is given by the following formula $\displaystyle \int a^xdx=\frac{a^x}{\ln(a)}$, where $a > 0$ and $a \neq 1$

Replace $u$ with the value that we assigned to it in the beginning: $3x$

Take the reciprocal of both sides of the equation

Move up the $-1$ from the denominator

Eliminate the $-2$ from the left side, multiplying both sides of the equation by the inverse of $-2$

Simplify $-\frac{1}{2}\left(\frac{1}{\frac{1}{3}e^{3x}+C_0}\right)$

Multiply the single term $2$ by each term of the polynomial $\left(\frac{1}{3}e^{3x}+C_0\right)$

We can rename $2C_0$ as other constant

We can take out the unknown from the exponent by applying natural logarithm to both sides of the equation

Apply the formula: $\ln\left(e^x\right)$$=x$, where $x=2y$

Eliminate the $2$ from the left side, multiplying both sides of the equation by the inverse of $2$