Final Answer
Step-by-step Solution
Specify the solving method
Since the integral $\int_{-2}^{2}\frac{1}{x^2-1}dx$ has a discontinuity inside the interval, we have to split it in two integrals
Learn how to solve definite integrals problems step by step online.
$\int_{-2}^{-1}\frac{1}{x^2-1}dx+\int_{-1}^{2}\frac{1}{x^2-1}dx$
Learn how to solve definite integrals problems step by step online. Integrate the function 1/(x^2-1) from -2 to 2. Since the integral \int_{-2}^{2}\frac{1}{x^2-1}dx has a discontinuity inside the interval, we have to split it in two integrals. Since the integral \int_{-1}^{2}\frac{1}{x^2-1}dx has a discontinuity inside the interval, we have to split it in two integrals. Factor the difference of squares x^2-1 as the product of two conjugated binomials. Factor the difference of squares x^2-1 as the product of two conjugated binomials.