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Rewrite the fraction $\frac{u}{u^2+a^2}$ inside the integral as the product of two functions: $u\frac{1}{u^2+a^2}$
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$\int u\frac{1}{u^2+a^2}du$
Learn how to solve differential calculus problems step by step online. Find the integral int(u/(u^2+a^2))du. Rewrite the fraction \frac{u}{u^2+a^2} inside the integral as the product of two functions: u\frac{1}{u^2+a^2}. We can solve the integral \int u\frac{1}{u^2+a^2}du by applying integration by parts method to calculate the integral of the product of two functions, using the following formula. First, identify u and calculate du. Now, identify dv and calculate v.