Final answer to the problem
Step-by-step Solution
Specify the solving method
Divide $x^2+1$ by $2x-3$
Learn how to solve trigonometric integrals problems step by step online.
$\begin{array}{l}\phantom{\phantom{;}2x\phantom{;}-3;}{\phantom{;}\frac{1}{2}x\phantom{;}+\frac{3}{4}\phantom{;}\phantom{;}}\\\phantom{;}2x\phantom{;}-3\overline{\smash{)}\phantom{;}x^{2}\phantom{-;x^n}+1\phantom{;}\phantom{;}}\\\phantom{\phantom{;}2x\phantom{;}-3;}\underline{-x^{2}+\frac{3}{2}x\phantom{;}\phantom{-;x^n}}\\\phantom{-x^{2}+\frac{3}{2}x\phantom{;};}\phantom{;}\frac{3}{2}x\phantom{;}+1\phantom{;}\phantom{;}\\\phantom{\phantom{;}2x\phantom{;}-3-;x^n;}\underline{-\frac{3}{2}x\phantom{;}+\frac{9}{4}\phantom{;}\phantom{;}}\\\phantom{;-\frac{3}{2}x\phantom{;}+\frac{9}{4}\phantom{;}\phantom{;}-;x^n;}\phantom{;}\frac{13}{4}\phantom{;}\phantom{;}\\\end{array}$
Learn how to solve trigonometric integrals problems step by step online. Find the integral int((x^2+1)/(2x-3))dx. Divide x^2+1 by 2x-3. Resulting polynomial. Expand the integral \int\left(\frac{1}{2}x+\frac{3}{4}+\frac{13}{4\left(2x-3\right)}\right)dx into 3 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int\frac{1}{2}xdx results in: \frac{1}{4}x^2.