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Expand the fraction $\frac{4x+24}{x^2-16}$ into $2$ simpler fractions with common denominator $x^2-16$
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$\int\left(\frac{4x}{x^2-16}+\frac{24}{x^2-16}\right)dx$
Learn how to solve integral calculus problems step by step online. Find the integral int((4x+24)/(x^2-16))dx. Expand the fraction \frac{4x+24}{x^2-16} into 2 simpler fractions with common denominator x^2-16. Simplify the expression inside the integral. The integral 4\int\frac{x}{x^2-16}dx results in: -4\ln\left(\frac{4}{\sqrt{x^2-16}}\right). The integral \int\frac{24}{x^2-16}dx results in: -3\ln\left(x+4\right)+3\ln\left(x-4\right).