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Find the integral $\int\frac{1}{\sqrt{4+2x^2}}dx$

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Definite integral of rational function | AP Calculus AB | Khan Academy

https://www.youtube.com/watch?v=4WJUEXIksH0

Implicit differentiation | Advanced derivatives | AP Calculus AB | Khan Academy

https://www.youtube.com/watch?v=mSVrqKZDRF4

Algebra 2 - Using quotient rule of logarithms to solve an equation, log4 (n + 1) - log4 (n - 2) = 1

https://www.youtube.com/watch?v=Ud2fy5kZUpo

Calculus - Learn how to take derivative using quotient rule by simplifying first, f(x)=x(1- 4/(x+3))

https://www.youtube.com/watch?v=Mqjiw5Ax_4w

Calculus - Take the log of both sides to find the derivative, y = (x(x^2 + 1)^2)/(sqrt(2x^2 - 1))

https://www.youtube.com/watch?v=7aF6Ck6ZRxw

Pre-Calculus - Mulitplying by the LCM to simplify a complex fraction, (1/4 + 2/3)/(5/6 - 1/12)

https://www.youtube.com/watch?v=Cz-Gq4tqQ6c

Function Plot

Plotting: $\frac{\sqrt{2}}{2}\ln\left(\frac{\sqrt{4+2x^2}}{2}+\frac{\sqrt{2}}{2}x\right)+C_0$

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0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Differential Calculus

The derivative of a function of a real variable measures the sensitivity to change of a quantity (a function value or dependent variable) which is determined by another quantity (the independent variable). Derivatives are a fundamental tool of calculus.

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