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Find the roots of $\frac{x-1}{x+1}=6$

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 Solution

 Videos

Algebra 2 - Determine and describe the discriminant 5x^2 - x -1 = 0

https://www.youtube.com/watch?v=F3eTBxCnzvI

Finding zeros of polynomials (1 of 2) | Mathematics III | High School Math | Khan Academy

https://www.youtube.com/watch?v=x9lb_frpkH0

Solving quadratics by taking square roots examples | High School Math | Khan Academy

https://www.youtube.com/watch?v=VTlvg4wJ1X0

Tutorial - How to solve a equation using difference of two angles, cos(x + (pi)/6)-cos(x - (pi)/6)=1

https://www.youtube.com/watch?v=f-HJVxlmuKM

Solving square-root equations: no solution | Mathematics III | High School Math | Khan Academy

https://www.youtube.com/watch?v=ibeyn2QGjCM

Algebra 2 - How to find all the roots of a polynomial by factoring, y = 6x^3 + x^2 - x

https://www.youtube.com/watch?v=Qi20wNdicXQ

 Function Plot

Plotting: $\frac{x-1}{x+1}-6$

SnapXam A²

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1

2

3

4

5

6

7

8

9

0



a

b

c

d

f

g

m

n

u

v

w

x

y

z

.

(◻)

+

-

×

◻/◻

/

÷

◻²

◻^◻

√◻

√

^◻√◻

^◻√

∞

e

π

ln

log

log_◻

lim

d/dx

D^□_x

∫

∫^◻

|◻|

θ

=

>

<

>=

<=

sin

cos

tan

cot

sec

csc

asin

acos

atan

acot

asec

acsc

sinh

cosh

tanh

coth

sech

csch

asinh

acosh

atanh

acoth

asech

acsch

 How to improve your answer:

Main Topic: Equations

In mathematics, an equation is a statement of an equality containing one or more variables. Solving the equation consists of determining which values of the variables make the equality true. In this situation, variables are also known as unknowns and the values which satisfy the equality are known as solutions.

Related Topics

Equations