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Find the integral of $\frac{x^3+x+1}{x\left(2x-5\right)^3\left(x^2+2x+5\right)^2}$

Step-by-step Solution

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Final answer to the problem

$-\frac{1}{3124}\ln\left(x\right)+\frac{-\frac{1}{138}}{\left(2x-5\right)^{2}}-\frac{1}{959}\left(\frac{1}{2}\arctan\left(\frac{x+1}{2}\right)+\frac{x+1}{4+\left(x+1\right)^2}\right)+\frac{-\frac{1}{928}}{4+\left(x+1\right)^2}+\frac{1}{9999}\ln\left(2x-5\right)+\frac{\frac{1}{603}}{2x-5}+\frac{1}{2503}\arctan\left(\frac{x+1}{2}\right)+\frac{1}{9091}\ln\left(4+\left(x+1\right)^2\right)+C_0$
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Step-by-step Solution

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Find the integral

$\int\frac{x^3+x+1}{x\left(2x-5\right)^3\left(x^2+2x+5\right)^2}dx$

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$\int\frac{x^3+x+1}{x\left(2x-5\right)^3\left(x^2+2x+5\right)^2}dx$

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Learn how to solve integral calculus problems step by step online. Find the integral of (x^3+x+1)/(x(2x-5)^3(x^2+2x+5)^2). Find the integral. Rewrite the fraction \frac{x^3+x+1}{x\left(2x-5\right)^3\left(x^2+2x+5\right)^2} in 6 simpler fractions using partial fraction decomposition. Find the values for the unknown coefficients: A, B, C, D, F, G, H, I. The first step is to multiply both sides of the equation from the previous step by x\left(2x-5\right)^3\left(x^2+2x+5\right)^2. Multiplying polynomials.

Final answer to the problem

$-\frac{1}{3124}\ln\left(x\right)+\frac{-\frac{1}{138}}{\left(2x-5\right)^{2}}-\frac{1}{959}\left(\frac{1}{2}\arctan\left(\frac{x+1}{2}\right)+\frac{x+1}{4+\left(x+1\right)^2}\right)+\frac{-\frac{1}{928}}{4+\left(x+1\right)^2}+\frac{1}{9999}\ln\left(2x-5\right)+\frac{\frac{1}{603}}{2x-5}+\frac{1}{2503}\arctan\left(\frac{x+1}{2}\right)+\frac{1}{9091}\ln\left(4+\left(x+1\right)^2\right)+C_0$

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Function Plot

Plotting: $-\frac{1}{3124}\ln\left(x\right)+\frac{-\frac{1}{138}}{\left(2x-5\right)^{2}}-\frac{1}{959}\left(\frac{1}{2}\arctan\left(\frac{x+1}{2}\right)+\frac{x+1}{4+\left(x+1\right)^2}\right)+\frac{-\frac{1}{928}}{4+\left(x+1\right)^2}+\frac{1}{9999}\ln\left(2x-5\right)+\frac{\frac{1}{603}}{2x-5}+\frac{1}{2503}\arctan\left(\frac{x+1}{2}\right)+\frac{1}{9091}\ln\left(4+\left(x+1\right)^2\right)+C_0$

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2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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Main Topic: Integral Calculus

Integration assigns numbers to functions in a way that can describe displacement, area, volume, and other concepts that arise by combining infinitesimal data.

Used Formulas

7. See formulas

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