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Find the roots of the polynomial $\frac{x^2-6x-8}{x-4}$ by putting it in the form of an equation and then set it equal to zero
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$\frac{x^2-6x-8}{x-4}=0$
Learn how to solve equations problems step by step online. Find the roots of (x^2-6x+-8)/(x-4). Find the roots of the polynomial \frac{x^2-6x-8}{x-4} by putting it in the form of an equation and then set it equal to zero. Multiply both sides of the equation by x-4. To find the roots of a polynomial of the form ax^2+bx+c we use the quadratic formula, where in this case a=1, b=-6 and c=-8. Then substitute the values of the coefficients of the equation in the quadratic formula: \displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}. Simplifying.