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Find the roots of $\frac{x^2-5x+16}{\left(2x+1\right)\left(x-2\right)}$

Step-by-step Solution

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Final Answer

$x=\frac{5+6.244998i}{2},\:x=\frac{5-6.244998i}{2}$
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Step-by-step Solution

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Find the roots of the equation using the Quadratic Formula

$\frac{x^2-5x+16}{\left(2x+1\right)\left(x-2\right)}=0$

Learn how to solve differential equations problems step by step online.

$\frac{x^2-5x+16}{\left(2x+1\right)\left(x-2\right)}=0$

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Learn how to solve differential equations problems step by step online. Find the roots of (x^2-5x+16)/((2x+1)(x-2)). Find the roots of the equation using the Quadratic Formula. Multiply both sides of the equation by \left(2x+1\right)\left(x-2\right). To find the roots of a polynomial of the form ax^2+bx+c we use the quadratic formula, where in this case a=1, b=-5 and c=16. Then substitute the values of the coefficients of the equation in the quadratic formula: \displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}. Simplifying.

Final Answer

$x=\frac{5+6.244998i}{2},\:x=\frac{5-6.244998i}{2}$

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Function Plot

Plotting: $\frac{x^2-5x+16}{\left(2x+1\right)\left(x-2\right)}$

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1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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Main Topic: Differential Equations

A differential equation is a mathematical equation that relates some function with its derivatives.

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