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$\int\frac{x^2-3x-7}{\left(x+1\right)^2\left(2x+3\right)}dx$
Learn how to solve integral calculus problems step by step online. Find the integral of (x^2-3x+-7)/((x+1)^2(2x+3)). Find the integral. Rewrite the fraction \frac{x^2-3x-7}{\left(x+1\right)^2\left(2x+3\right)} in 3 simpler fractions using partial fraction decomposition. Find the values for the unknown coefficients: A, B, C. The first step is to multiply both sides of the equation from the previous step by \left(x+1\right)^2\left(2x+3\right). Multiplying polynomials.