Find the derivative of $\frac{\frac{x^2+2xy+y^2}{x^2-y^2}\left(2x^2-xy-y^2\right)}{x^2-xy-2y^2}$

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$\frac{d}{dx}\left(\frac{\left(x^2+2xy+y^2\right)\left(2x^2-xy-y^2\right)}{\left(x^2-y^2\right)\left(x^2-xy-2y^2\right)}\right)$

Learn how to solve integral calculus problems step by step online. Find the derivative of ((x^2+2xyy^2)/(x^2-y^2)(2x^2-xy-y^2))/(x^2-xy-2y^2). Simplifying. Apply the quotient rule for differentiation, which states that if f(x) and g(x) are functions and h(x) is the function defined by {\displaystyle h(x) = \frac{f(x)}{g(x)}}, where {g(x) \neq 0}, then {\displaystyle h'(x) = \frac{f'(x) \cdot g(x) - g'(x) \cdot f(x)}{g(x)^2}}. The power of a product is equal to the product of it's factors raised to the same power. Simplify the product -(x^2+2xy+y^2).