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Simplify the expression $\frac{x+1}{x-1}$

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Limit

$\lim_{x\to1}\left(\frac{x+1}{x-1}\right)=\mathrm{The\:limit\:does\:not\:exist}$ See full solution

Derivative

$\frac{d}{dx}\left(\frac{x+1}{x-1}\right)=\frac{x-1-x-1}{\left(x-1\right)^2}$ See full solution

Integral

$\int\frac{x+1}{x-1}dx=2\ln\left(x-1\right)+x+C_1$ See full solution

Main Topic: Implicit Differentiation

Implicit differentiation makes use of the chain rule to differentiate implicitly defined functions. For differentiating an implicit function y(x), defined by an equation R(x, y) = 0, it is not generally possible to solve it explicitly for y(x) and then differentiate. Instead, one can differentiate R(x, y) with respect to x and y and then solve a linear equation in dy/dx for getting explicitly the derivative in terms of x and y.

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