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# Find the implicit derivative $\frac{d}{dx}\left(y=\sec\left(x\right)\right)$

## Step-by-step Solution

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ln
log
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sin
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tan
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asin
acos
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sinh
cosh
tanh
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asinh
acosh
atanh
acoth
asech
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### Videos

$y^{\prime}=\sec\left(x\right)\tan\left(x\right)$
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## Step-by-step Solution

Problem to solve:

$\frac{d}{dx}\left(y=\sec\left(x\right)\right)$
1

Apply implicit differentiation by taking the derivative of both sides of the equation with respect to the differentiation variable

$\frac{d}{dx}\left(y\right)=\frac{d}{dx}\left(\sec\left(x\right)\right)$

Learn how to solve implicit differentiation problems step by step online.

$\frac{d}{dx}\left(y\right)=\frac{d}{dx}\left(\sec\left(x\right)\right)$

Learn how to solve implicit differentiation problems step by step online. Find the implicit derivative (d/dx)(y=sec(x)). Apply implicit differentiation by taking the derivative of both sides of the equation with respect to the differentiation variable. The derivative of the linear function is equal to 1. Taking the derivative of secant function: \frac{d}{dx}\left(\sec(x)\right)=\sec(x)\cdot\tan(x)\cdot D_x(x).

$y^{\prime}=\sec\left(x\right)\tan\left(x\right)$
SnapXam A2

### beta Got another answer? Verify it!

Go!
1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

$\frac{d}{dx}\left(y=\sec\left(x\right)\right)$

### Main topic:

Implicit Differentiation

~ 0.02 s