Final Answer
Step-by-step Solution
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Apply the product rule for differentiation: $(f\cdot g)'=f'\cdot g+f\cdot g'$, where $f=e^x$ and $g=2xy+yx^2+\frac{y^3}{3}$
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$\frac{d}{dy}\left(e^x\right)\left(2xy+yx^2+\frac{y^3}{3}\right)+e^x\frac{d}{dy}\left(2xy+yx^2+\frac{y^3}{3}\right)$
Learn how to solve product rule of differentiation problems step by step online. Find the derivative using the product rule d/dy(e^x(2xy+yx^2(y^3)/3)). Apply the product rule for differentiation: (f\cdot g)'=f'\cdot g+f\cdot g', where f=e^x and g=2xy+yx^2+\frac{y^3}{3}. The derivative of the constant function (e^x) is equal to zero. Any expression multiplied by 0 is equal to 0. x+0=x, where x is any expression.