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Find the derivative of $e^{\sin\left(t\right)}\ln\left(t^2+1\right)$ using the constant rule

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Step-by-step Solution

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Apply the product rule for differentiation: $(f\cdot g)'=f'\cdot g+f\cdot g'$, where $f=

$\frac{d}{dx}\left(e^{\sin\left(t\right)}\right)\ln\left(t^2+1\right)+\frac{d}{dx}\left(\ln\left(t^2+1\right)\right)e^{\sin\left(t\right)}$

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$\frac{d}{dx}\left(e^{\sin\left(t\right)}\right)\ln\left(t^2+1\right)+\frac{d}{dx}\left(\ln\left(t^2+1\right)\right)e^{\sin\left(t\right)}$

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Learn how to solve constant rule for differentiation problems step by step online. Find the derivative of e^sin(t)ln(t^2+1) using the constant rule. Apply the product rule for differentiation: (f\cdot g)'=f'\cdot g+f\cdot g', where f=. The derivative of the constant function (e^{\sin\left(t\right)}) is equal to zero. The derivative of the constant function (\ln\left(t^2+1\right)) is equal to zero. Simplify the derivative.

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Main Topic: Constant Rule for Differentiation

The constant rule for differentiation says that the derivative for any constant $k$ is equal to zero.

Used Formulas

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