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Find the derivative of $\sqrt{\frac{4+3x^2}{\sqrt[3]{x^2+1}}}\left(epi\right)^x$

Step-by-step Solution

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Final answer to the problem

$\frac{\left(epi\right)^x\left(6x^{3}+5x+2\ln\left(epi\right)^{3}x^2+9x^{4}\ln\left(epi\right)+12\ln\left(epi\right)\right)}{3\sqrt{4+3x^2}\sqrt[6]{\left(x^2+1\right)^{7}}}$
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Step-by-step Solution

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The power of a quotient is equal to the quotient of the power of the numerator and denominator: $\displaystyle\left(\frac{a}{b}\right)^n=\frac{a^n}{b^n}$

$\frac{d}{dx}\left(\frac{\sqrt{4+3x^2}}{\sqrt[6]{x^2+1}}\left(epi\right)^x\right)$

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$\frac{d}{dx}\left(\frac{\sqrt{4+3x^2}}{\sqrt[6]{x^2+1}}\left(epi\right)^x\right)$

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Learn how to solve problems step by step online. Find the derivative of ((4+3x^2)/((x^2+1)^1/3))^1/2(pie)^x. The power of a quotient is equal to the quotient of the power of the numerator and denominator: \displaystyle\left(\frac{a}{b}\right)^n=\frac{a^n}{b^n}. Multiplying the fraction by \left(epi\right)^x. Apply the quotient rule for differentiation, which states that if f(x) and g(x) are functions and h(x) is the function defined by {\displaystyle h(x) = \frac{f(x)}{g(x)}}, where {g(x) \neq 0}, then {\displaystyle h'(x) = \frac{f'(x) \cdot g(x) - g'(x) \cdot f(x)}{g(x)^2}}. Simplify \left(\sqrt[6]{x^2+1}\right)^2 using the power of a power property: \left(a^m\right)^n=a^{m\cdot n}. In the expression, m equals \frac{1}{6} and n equals 2.

Final answer to the problem

$\frac{\left(epi\right)^x\left(6x^{3}+5x+2\ln\left(epi\right)^{3}x^2+9x^{4}\ln\left(epi\right)+12\ln\left(epi\right)\right)}{3\sqrt{4+3x^2}\sqrt[6]{\left(x^2+1\right)^{7}}}$

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Function Plot

Plotting: $\frac{\left(epi\right)^x\left(6x^{3}+5x+2\ln\left(epi\right)^{3}x^2+9x^{4}\ln\left(epi\right)+12\ln\left(epi\right)\right)}{3\sqrt{4+3x^2}\sqrt[6]{\left(x^2+1\right)^{7}}}$

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5
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7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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