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Find the derivative of $\frac{d}{dx}\left(\sqrt{\frac{4+3x^2}{\sqrt[3]{x^2+1}}}\left(epi\right)^x\right)$

Step-by-step Solution

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Final Answer

$\frac{9\left(x^2+1\right)\left(epi\right)^x\cdot x+\left(-4-3x^2\right)\left(epi\right)^x\cdot x+3\left(x^2+1\right)\left(4+3x^2\right)\left(epi\right)^x\ln\left(epi\right)}{3\sqrt[6]{\left(x^2+1\right)^{7}}\sqrt{4+3x^2}}$
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Step-by-step Solution

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The power of a quotient is equal to the quotient of the power of the numerator and denominator: $\displaystyle\left(\frac{a}{b}\right)^n=\frac{a^n}{b^n}$

$\frac{d}{dx}\left(\frac{\sqrt{4+3x^2}}{\sqrt[6]{x^2+1}}\left(epi\right)^x\right)$

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$\frac{d}{dx}\left(\frac{\sqrt{4+3x^2}}{\sqrt[6]{x^2+1}}\left(epi\right)^x\right)$

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Learn how to solve problems step by step online. Find the derivative of d/dx(((4+3x^2)/((x^2+1)^1/3))^1/2(pie)^x). The power of a quotient is equal to the quotient of the power of the numerator and denominator: \displaystyle\left(\frac{a}{b}\right)^n=\frac{a^n}{b^n}. Multiplying the fraction by \left(epi\right)^x. Apply the quotient rule for differentiation, which states that if f(x) and g(x) are functions and h(x) is the function defined by {\displaystyle h(x) = \frac{f(x)}{g(x)}}, where {g(x) \neq 0}, then {\displaystyle h'(x) = \frac{f'(x) \cdot g(x) - g'(x) \cdot f(x)}{g(x)^2}}. Simplify \left(\sqrt[6]{x^2+1}\right)^2 using the power of a power property: \left(a^m\right)^n=a^{m\cdot n}. In the expression, m equals \frac{1}{6} and n equals 2.

Final Answer

$\frac{9\left(x^2+1\right)\left(epi\right)^x\cdot x+\left(-4-3x^2\right)\left(epi\right)^x\cdot x+3\left(x^2+1\right)\left(4+3x^2\right)\left(epi\right)^x\ln\left(epi\right)}{3\sqrt[6]{\left(x^2+1\right)^{7}}\sqrt{4+3x^2}}$

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Function Plot

Plotting: $\frac{9\left(x^2+1\right)\left(epi\right)^x\cdot x+\left(-4-3x^2\right)\left(epi\right)^x\cdot x+3\left(x^2+1\right)\left(4+3x^2\right)\left(epi\right)^x\ln\left(epi\right)}{3\sqrt[6]{\left(x^2+1\right)^{7}}\sqrt{4+3x^2}}$

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0
a
b
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d
f
g
m
n
u
v
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x
y
z
.
(◻)
+
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×
◻/◻
/
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e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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