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Find the implicit derivative $\frac{d}{dx}\left(\sqrt[3]{ax^2}+\sqrt[3]{by^2}=\sqrt[3]{cx}\right)$

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Implicit differentiation | Advanced derivatives | AP Calculus AB | Khan Academy

https://www.youtube.com/watch?v=mSVrqKZDRF4

Worked example: Evaluating derivative with implicit differentiation | AP Calculus AB | Khan Academy

https://www.youtube.com/watch?v=KyYC8XzKsHU

Implicit Differentiation - Find The First &amp; Second Derivatives

https://www.youtube.com/watch?v=-XQDh6Z6DPI

Calculus - Find the derivative of natural logarithm using product property, d(ln(2x))/dx

https://www.youtube.com/watch?v=urYZhqwUTI0

Derivative of x^x^x, Logarithmic Differentiation of Exponential Functions, Calculus Youtube Video

https://www.youtube.com/watch?v=Vhltl9w6QNM

Equation of a tangent line | Taking derivatives | Differential Calculus | Khan Academy

https://www.youtube.com/watch?v=1KwW1v__T_0

Function Plot

Plotting: $\frac{2\sqrt[3]{a}}{3\sqrt[3]{x}}+\frac{2}{3\sqrt[3]{b^{2}}\sqrt[3]{y^{4}}}by\cdot y^{\prime}=\frac{\sqrt[3]{c}}{3\sqrt[3]{x^{2}}}$

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0
a
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m
n
u
v
w
x
y
z
.
(◻)
+
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×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Differential Calculus

The derivative of a function of a real variable measures the sensitivity to change of a quantity (a function value or dependent variable) which is determined by another quantity (the independent variable). Derivatives are a fundamental tool of calculus.

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