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Find the derivative using the product rule $\frac{d}{dx}\left(\frac{3x^2}{\sqrt[5]{a^7}}\left(20-e^{\frac{1}{100}x}\right)\right)$

Step-by-step Solution

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Final Answer

$\frac{x\left(120-6e^{\frac{1}{100}x}-\frac{3}{100}xe^{\frac{1}{100}x}\right)}{\sqrt[5]{a^{7}}}$
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Step-by-step Solution

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$\frac{d}{dx}\left(\frac{3x^2\left(20-e^{\frac{1}{100}x}\right)}{\sqrt[5]{a^{7}}}\right)$

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$\frac{d}{dx}\left(\frac{3x^2\left(20-e^{\frac{1}{100}x}\right)}{\sqrt[5]{a^{7}}}\right)$

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Learn how to solve product rule of differentiation problems step by step online. Find the derivative using the product rule d/dx((3x^2)/(a^7^1/5)(20-e^(1/100x))). Simplifying. The derivative of a function multiplied by a constant (\frac{1}{\sqrt[5]{a^{7}}}) is equal to the constant times the derivative of the function. Apply the product rule for differentiation: (f\cdot g)'=f'\cdot g+f\cdot g'. The derivative of the constant function (3) is equal to zero.

Final Answer

$\frac{x\left(120-6e^{\frac{1}{100}x}-\frac{3}{100}xe^{\frac{1}{100}x}\right)}{\sqrt[5]{a^{7}}}$

Explore different ways to solve this problem

Solving a math problem using different methods is important because it enhances understanding, encourages critical thinking, allows for multiple solutions, and develops problem-solving strategies. Read more

Find the derivativeFind derivative of 3x^2/(a^7^0.2)(20+-1e^0.01x) using the quotient ruleFind derivative of 3x^2/(a^7^0.2)(20+-1e^0.01x) using logarithmic differentiationFind derivative of 3x^2/(a^7^0.2)(20+-1e^0.01x) using the definition

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Function Plot

Plotting: $\frac{x\left(120-6e^{\frac{1}{100}x}-\frac{3}{100}xe^{\frac{1}{100}x}\right)}{\sqrt[5]{a^{7}}}$

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0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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Main Topic: Product Rule of differentiation

The product rule is a formula used to find the derivatives of products of two or more functions. It may be stated as $(f\cdot g)'=f'\cdot g+f\cdot g'$

Used Formulas

6. See formulas

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