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Find the higher order ($2$) derivative of $\frac{1}{x^2-1}$

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 Solution

 Videos

Algebra 2 - Evaluating functions for numeric values, p(x) = 2x^2 - 4x + 1. Find p(2) and p(-1)

https://www.youtube.com/watch?v=POdNjomXHWA

Finding zeros of polynomials (1 of 2) | Mathematics III | High School Math | Khan Academy

https://www.youtube.com/watch?v=x9lb_frpkH0

Algebra 2 - Learn how to divide using long division with multiple zeros, (x^5 - 1) / (x - 1)

https://www.youtube.com/watch?v=QLmbtmqii9o

Calculus: Derivatives 2 | Taking derivatives | Differential Calculus | Khan Academy

https://www.youtube.com/watch?v=ay8838UZ4nM

Calculus - Take the log of both sides to find the derivative, y = (x(x^2 + 1)^2)/(sqrt(2x^2 - 1))

https://www.youtube.com/watch?v=7aF6Ck6ZRxw

Algebra 2 - Describe and solve for the zeros using quadratic formula x^2 - 4x + 40 = 0

https://www.youtube.com/watch?v=1tzMPeAmo1Q

 Function Plot

Plotting: $\frac{-2\left(x^2-1\right)^2+8x^2\left(x^2-1\right)}{\left(x^2-1\right)^{4}}$

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1

2

3

4

5

6

7

8

9

0



a

b

c

d

f

g

m

n

u

v

w

x

y

z

.

(◻)

+

-

×

◻/◻

/

÷

◻²

◻^◻

√◻

√

^◻√◻

^◻√

∞

e

π

ln

log

log_◻

lim

d/dx

D^□_x

∫

∫^◻

|◻|

θ

=

>

<

>=

<=

sin

cos

tan

cot

sec

csc

asin

acos

atan

acot

asec

acsc

sinh

cosh

tanh

coth

sech

csch

asinh

acosh

atanh

acoth

asech

acsch

 How to improve your answer:

 Main Topic: Polynomial long division

In algebra, polynomial long division is an algorithm for dividing a polynomial by another polynomial of the same or lower degree, a generalised version of the familiar arithmetic technique called long division.

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