Final Answer
$\frac{6x^5-5x^3-49x-14x^2+23x^4+20}{3x^3-5+x^2}$
Step-by-step explanation
Problem to solve:
$\frac{6x^5-5x^3-35x-14x-14x^2+23x^4+20}{3x^3-5+x^2}$
1
Combining like terms $-35x$ and $-14x$
$\frac{6x^5-5x^3-49x-14x^2+23x^4+20}{3x^3-5+x^2}$
Final Answer
$\frac{6x^5-5x^3-49x-14x^2+23x^4+20}{3x^3-5+x^2}$