Final Answer
$\frac{\left(b+1\right)\left(b-9\right)}{b-3}$
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Step-by-step Solution
Specify the solving method
1
Factor the trinomial $b^2-8b-9$ finding two numbers that multiply to form $-9$ and added form $-8$
$\begin{matrix}\left(1\right)\left(-9\right)=-9\\ \left(1\right)+\left(-9\right)=-8\end{matrix}$
2
Thus
$\frac{\left(b+1\right)\left(b-9\right)}{b-3}$
Final Answer
$\frac{\left(b+1\right)\left(b-9\right)}{b-3}$