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Simplify the expression $\frac{x\cos\left(x\right)^2}{\cos\left(x\right)^4+\sin\left(x\right)^4+1}$

Step-by-step Solution

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Final answer to the problem

$\frac{x-x\sin\left(x\right)^2}{\cos\left(x\right)^4+\sin\left(x\right)^4+1}$
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Step-by-step Solution

How should I solve this problem?

  • Choose an option
  • Write in simplest form
  • Solve by quadratic formula (general formula)
  • Find the derivative using the definition
  • Simplify
  • Find the integral
  • Find the derivative
  • Factor
  • Factor by completing the square
  • Find the roots
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1

Applying the pythagorean identity: $\cos^2(\theta)=1-\sin(\theta)^2$

$\frac{x\left(1-\sin\left(x\right)^2\right)}{\cos\left(x\right)^4+\sin\left(x\right)^4+1}$
Why is 1 - sin(x)^2 = cos(x)^2 ?
2

Multiply the single term $x$ by each term of the polynomial $\left(1-\sin\left(x\right)^2\right)$

$\frac{x-x\sin\left(x\right)^2}{\cos\left(x\right)^4+\sin\left(x\right)^4+1}$

Final answer to the problem

$\frac{x-x\sin\left(x\right)^2}{\cos\left(x\right)^4+\sin\left(x\right)^4+1}$

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Function Plot

Plotting: $\frac{x-x\sin\left(x\right)^2}{\cos\left(x\right)^4+\sin\left(x\right)^4+1}$

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Answer Assistant

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Got a different answer? Verify it!

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1
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3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Differential Calculus

The derivative of a function of a real variable measures the sensitivity to change of a quantity (a function value or dependent variable) which is determined by another quantity (the independent variable). Derivatives are a fundamental tool of calculus.

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