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$\int\frac{4x^3-9x}{2x^3-7x^2-15x}dx$
Learn how to solve problems step by step online. Find the integral of (4x^3-9x)/(2x^3-7x^2-15x). Find the integral. Divide 4x^3-9x by 2x^3-7x^2-15x. Resulting polynomial. Expand the integral \int\left(2+\frac{14x^{2}+21x}{2x^3-7x^2-15x}\right)dx into 2 integrals using the sum rule for integrals, to then solve each integral separately.