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$\int\frac{4x^3-9x}{2x^3-7x^2-15x}dx$
Learn how to solve integral calculus problems step by step online. Integrate the function (4x^3-9x)/(2x^3-7x^2-15x). Find the integral. Rewrite the expression \frac{4x^3-9x}{2x^3-7x^2-15x} inside the integral in factored form. Rewrite the expression \frac{4x^3-9x}{x\left(2x+3\right)\left(x-5\right)} inside the integral in factored form. Expand the fraction \frac{2x-3}{x-5} into 2 simpler fractions with common denominator x-5.