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Add the values $5$ and $7$
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$derivdef\left(\frac{3-2x}{12}\right)$
Learn how to solve definition of derivative problems step by step online. Find the derivative of (3-2x)/(5+7) using the definition. Add the values 5 and 7. Find the derivative of \frac{3-2x}{12} using the definition. Apply the definition of the derivative: \displaystyle f'(x)=\lim_{h\to0}\frac{f(x+h)-f(x)}{h}. The function f(x) is the function we want to differentiate, which is \frac{3-2x}{12}. Substituting f(x+h) and f(x) on the limit, we get. Combine \frac{3-2\left(x+h\right)}{12}-\frac{3-2x}{12} in a single fraction. Divide fractions \frac{\frac{3-2\left(x+h\right)-\left(3-2x\right)}{12}}{h} with Keep, Change, Flip: \frac{a}{b}\div c=\frac{a}{b}\div\frac{c}{1}=\frac{a}{b}\times\frac{1}{c}=\frac{a}{b\cdot c}.