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Find the roots of the equation using the Quadratic Formula
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$\frac{3}{x-2}+\frac{2x+3}{x^2+2x+4}+\frac{-\left(6x+12\right)}{x^3-8}=0$
Learn how to solve equations problems step by step online. Find the roots of 3/(x-2)+(2x+3)/(x^2+2x+4)(-(6x+12))/(x^3-8). Find the roots of the equation using the Quadratic Formula. Simplify the product -(6x+12). Given a pair of cubes to factor: x^3-8, start by rewriting both terms to the cubic power. Factor the sum or difference of cubes using the formula: a^3\pm b^3 = (a\pm b)(a^2\mp ab+b^2).