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Solve the equation $\frac{3}{2}\left(\frac{1}{6}x+\frac{4}{3}\right)=\frac{2}{5}x-\frac{3}{5}$

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Solution

Videos

Equations with rational expressions | Mathematics III | High School Math | Khan Academy

https://www.youtube.com/watch?v=McOMtxI_Jzs

Algebra 2 - Factoring a trinomial when a is greater than one now you know solve 2x^2 + 5x -3 = 0

https://www.youtube.com/watch?v=DZWgxGACroM

Algebra 2 - using the square root method to solve a quadratic equation 4x^2 - 4x + 1 = 9

https://www.youtube.com/watch?v=90FQ2oLoEEQ

Solving an equation with a variable on both sides one solution ex1, 5g+4(–5+3g)=1–g

https://www.youtube.com/watch?v=fWhmu4naD_s

Algebra 2 - Learning to solve rational equations in math class ((x+3)/(x‐2)) + (5/(x^2‐4)) = 1

https://www.youtube.com/watch?v=y8p0Tpn3BcI

Algebra: Linear equations 2 | Linear equations | Algebra I | Khan Academy

https://www.youtube.com/watch?v=DopnmxeMt-s

Function Plot

Plotting: $\frac{3}{2}\left(\frac{1}{6}x+\frac{4}{3}\right)+\frac{2}{5}x+\frac{3}{5}$

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9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
◻2
◻◻
√◻
√

◻√◻
◻√
∞
e
π
ln
log
log◻
lim
d/dx
D□x
∫
∫◻
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Similar Problems Solved

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$\frac{x+2}{3}=\frac{2x-1}{14}$

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$\frac{6x+7}{3}=\frac{9x+3}{7}$

$\left(\frac{n}{3}\right)=\left(\frac{n}{2}\right)$

$\frac{2x-7}{7}=\frac{9x-2}{3}$

Main Topic: One-variable linear equations

Algebraic equations that have just one variable.

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