$14>x$
$0\cdot\left(-3\right)\cdot\left(-3\right)$
$x.\frac{4}{5}.\frac{2}{3}.\frac{6}{7}$
$\frac{\:-\sin^2\left(x\right)-2}{3\sin\left(x\right)}=0$
$\left(4x+13y\right)^2$
$\left(\frac{1}{5}m^3-\frac{1}{5}n^3\right)$
$5x-10>3x-2$
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