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Factor the difference of squares $1-x^4$ as the product of two bynomials: $a^2-b^2=(a+b)(a-b)$
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$\frac{1-x^{12}}{\left(1+x^2\right)\left(1-x^2\right)}$
Learn how to solve polynomial factorization problems step by step online. Factor by completing the square (1-x^12)/(1-x^4). Factor the difference of squares 1-x^4 as the product of two bynomials: a^2-b^2=(a+b)(a-b). Factor the sum or difference of cubes using the formula: a^3\pm b^3 = (a\pm b)(a^2\mp ab+b^2). The difference of the squares of two terms, divided by the sum of the same terms, is equal to the difference of the terms. In other words: \displaystyle\frac{a^2-b^2}{a+b}=a-b.. Simplify the fraction \frac{\left(1-x^2\right)\left(1+x^{4}+x^{8}\right)}{1-x^2} by 1-x^2.