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Find the break even points of the polynomial $\frac{-2}{\frac{x^3+8}{x^4-16}}$ by putting it in the form of an equation and then set it equal to zero
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$\frac{-2}{\frac{x^3+8}{x^4-16}}=0$
Learn how to solve integral calculus problems step by step online. Find the break even points of the expression -2/((x^3+8)/(x^4-16)). Find the break even points of the polynomial \frac{-2}{\frac{x^3+8}{x^4-16}} by putting it in the form of an equation and then set it equal to zero. Divide fractions \frac{-2}{\frac{x^3+8}{x^4-16}} with Keep, Change, Flip: a\div \frac{b}{c}=\frac{a}{1}\div\frac{b}{c}=\frac{a}{1}\times\frac{c}{b}=\frac{a\cdot c}{b}. Multiply both sides of the equation by x^3+8. Divide both sides of the equation by -2.