Final Answer
Step-by-step Solution
Specify the solving method
Starting from the left-hand side (LHS) of the identity
Multiply and divide the fraction $\frac{\sec\left(x\right)+1}{\tan\left(x\right)}$ by the conjugate of it's numerator $\sec\left(x\right)+1$
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$\frac{\sec\left(x\right)+1}{\tan\left(x\right)}$
Learn how to solve trigonometric identities problems step by step online. Prove the trigonometric identity (sec(x)+1)/tan(x)=tan(x)/(sec(x)-1). Starting from the left-hand side (LHS) of the identity. Multiply and divide the fraction \frac{\sec\left(x\right)+1}{\tan\left(x\right)} by the conjugate of it's numerator \sec\left(x\right)+1. Multiplying fractions \frac{\sec\left(x\right)+1}{\tan\left(x\right)} \times \frac{\sec\left(x\right)-1}{\sec\left(x\right)-1}. The sum of two terms multiplied by their difference is equal to the square of the first term minus the square of the second term. In other words: (a+b)(a-b)=a^2-b^2..