Try NerdPal! Our new app on iOS and Android

Prove the trigonometric identity $\tan\left(x\right)+\cot\left(x\right)=\sec\left(x\right)\csc\left(x\right)$

Step-by-step Solution

Go!
Go!
1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

Final Answer

true

Step-by-step Solution

Problem to solve:

$\tan\left(x\right)+\cot\left(x\right)=\sec\left(x\right)\csc\left(x\right)$

Specify the solving method

1

Applying the trigonometric identity: $\cot\left(\theta\right)=\frac{1}{\tan\left(\theta\right)}$

$\tan\left(x\right)+\frac{1}{\tan\left(x\right)}=\sec\left(x\right)\csc\left(x\right)$

Learn how to solve trigonometric identities problems step by step online.

$\tan\left(x\right)+\frac{1}{\tan\left(x\right)}=\sec\left(x\right)\csc\left(x\right)$

Unlock the first 3 steps of this solution!

Learn how to solve trigonometric identities problems step by step online. Prove the trigonometric identity tan(x)+cot(x)=sec(x)csc(x). Applying the trigonometric identity: \cot\left(\theta\right)=\frac{1}{\tan\left(\theta\right)}. Combine all terms into a single fraction with \tan\left(x\right) as common denominator. When multiplying two powers that have the same base (\tan\left(x\right)), you can add the exponents. Applying the trigonometric identity: \tan(x)^2+1=\sec(x)^2.

Final Answer

true
$\tan\left(x\right)+\cot\left(x\right)=\sec\left(x\right)\csc\left(x\right)$

Used formulas:

2. See formulas

Time to solve it:

~ 0.13 s