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Find the roots of the polynomial $\frac{\frac{1}{6x^5-4x^4+3x^2-9x+4}}{x^4-8x^3+9x-2}$ by putting it in the form of an equation and then set it equal to zero
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$\frac{\frac{1}{6x^5-4x^4+3x^2-9x+4}}{x^4-8x^3+9x-2}=0$
Learn how to solve equations problems step by step online. Find the roots of (1/(6x^5-4x^43x^2-9x+4))/(x^4-8x^39x+-2). Find the roots of the polynomial \frac{\frac{1}{6x^5-4x^4+3x^2-9x+4}}{x^4-8x^3+9x-2} by putting it in the form of an equation and then set it equal to zero. Divide fractions \frac{\frac{1}{6x^5-4x^4+3x^2-9x+4}}{x^4-8x^3+9x-2} with Keep, Change, Flip: \frac{a}{b}\div c=\frac{a}{b}\div\frac{c}{1}=\frac{a}{b}\times\frac{1}{c}=\frac{a}{b\cdot c}. No solutions exist for this equation.