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Find the derivative using logarithmic differentiation method $\frac{x^2-x+1}{\left(x^2-1\right)\left(x-1\right)^3}$

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 Solution

 Videos

Calculus: Derivatives 2 | Taking derivatives | Differential Calculus | Khan Academy

https://www.youtube.com/watch?v=ay8838UZ4nM

Use the product rule to take the derivative of an exponential equation

https://www.youtube.com/watch?v=otqQ3gpE6fQ

Taking the derivative of a exponential equation using the quotient rule

https://www.youtube.com/watch?v=kRmiW9OJy54

Calculus - Find the derivative of the inverse of a radical equation, f(x)=sqrt(x^2 +6x); find g'(4)

https://www.youtube.com/watch?v=ErarY1CS-bY

Pre-Calculus - Condensing a logarithmic expression to one logarithm 2[3lnx - ln(x+1)-ln(x-1)]

https://www.youtube.com/watch?v=HS0--oEAT4I

How do find the x and y intercepts and graph

https://www.youtube.com/watch?v=DVgB-6mFlXk

 Function Plot

Plotting: $\left(\frac{2x-1}{x^2-x+1}+\frac{-2x}{x^2-1}+\frac{-3}{x-1}\right)\frac{x^2-x+1}{\left(x^2-1\right)\left(x-1\right)^3}$

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1

2

3

4

5

6

7

8

9

0



a

b

c

d

f

g

m

n

u

v

w

x

y

z

.

(◻)

+

-

×

◻/◻

/

÷

◻²

◻^◻

√◻

√

^◻√◻

^◻√

∞

e

π

ln

log

log_◻

lim

d/dx

D^□_x

∫

∫^◻

|◻|

θ

=

>

<

>=

<=

sin

cos

tan

cot

sec

csc

asin

acos

atan

acot

asec

acsc

sinh

cosh

tanh

coth

sech

csch

asinh

acosh

atanh

acoth

asech

acsch

 How to improve your answer:

 Main Topic: Differential Equations

A differential equation is a mathematical equation that relates some function with its derivatives.

 Related Topics

Differential Equations