$xy+y=\left(xy\right)^3$
$x+10+x+12$
$\left(-4a-2b\right)\:\left(2b-4a\right)$
$\frac{d}{dx}\left(ln\left(x^2+6^x\right)\right)$
$\sec\left(x\right)+3=1$
$3x^2-18x-15=0$
$\frac{2x^{-2}y^{-2}z}{x^3z^{-2}}$
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