👉 Try now NerdPal! Our new math app on iOS and Android

Find the derivative using the product rule $y=\left(\sqrt{x}\right)^{2x}$

Related Videos

Go!
Symbolic mode
Text mode
Go!
1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

Use the product rule to take the derivative of an exponential equation

https://www.youtube.com/watch?v=otqQ3gpE6fQ

Calculus - Take the derivative using product rule with natural logarithms,, ln(y) = (x^2)ln(x)

https://www.youtube.com/watch?v=4TpfQj_Wj84

Worked example: Evaluating derivative with implicit differentiation | AP Calculus AB | Khan Academy

https://www.youtube.com/watch?v=KyYC8XzKsHU

Calculus - How to use the product rule then chain rule with secant, y = 5x^2 sec(3x)

https://www.youtube.com/watch?v=pWCM68zbW6s

How to take the derivative using chain rule with natural log and cosine

https://www.youtube.com/watch?v=bbK7KtEeULo

Derivative using chain rule inside product rule

https://www.youtube.com/watch?v=7s1PU4M38vw

Function Plot

Plotting: $\left(\ln\left(x\right)+1\right)x^x$

SnapXam A2
Answer Assistant

beta
Got a different answer? Verify it!

Go!
1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Differential Calculus

The derivative of a function of a real variable measures the sensitivity to change of a quantity (a function value or dependent variable) which is determined by another quantity (the independent variable). Derivatives are a fundamental tool of calculus.

Used Formulas

See formulas (5)

Your Math & Physics Tutor. Powered by AI

Available 24/7, 365.

Unlimited step-by-step math solutions. No ads.

Includes multiple solving methods.

Support for more than 100 math topics.

Premium access on our iOS and Android apps as well.

20% discount on online tutoring.

Choose your subscription plan:
Have a promo code?
Pay $39.97 USD securely with your payment method.
Please hold while your payment is being processed.
Create an Account