Find the limit of $\frac{x^2+x}{\left(x+3\right)^2}$ as $x$ approaches $\infty $

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Final answer to the problem

$1$
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Step-by-step Solution

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  • Solve without using l'Hôpital
  • Solve using L'Hôpital's rule
  • Solve using limit properties
  • Solve using direct substitution
  • Solve the limit using factorization
  • Solve the limit using rationalization
  • Integrate by partial fractions
  • Product of Binomials with Common Term
  • FOIL Method
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1

Expand the expression $\left(x+3\right)^2$ using the square of a binomial: $(a+b)^2=a^2+2ab+b^2$

$\lim_{x\to\infty }\left(\frac{x^2+x}{x^{2}+6x+9}\right)$

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$\lim_{x\to\infty }\left(\frac{x^2+x}{x^{2}+6x+9}\right)$

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Learn how to solve limits to infinity problems step by step online. Find the limit of (x^2+x)/((x+3)^2) as x approaches infinity. Expand the expression \left(x+3\right)^2 using the square of a binomial: (a+b)^2=a^2+2ab+b^2. As it's an indeterminate limit of type \frac{\infty}{\infty}, divide both numerator and denominator by the term of the denominator that tends more quickly to infinity (the term that, evaluated at a large value, approaches infinity faster). In this case, that term is . Separate the terms of both fractions. Simplify the fraction .

Final answer to the problem

$1$

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Function Plot

Plotting: $\frac{x^2+x}{\left(x+3\right)^2}$

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5
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7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Limits to Infinity

The limit of a function f(x) when x tends to infinity is the value that the function takes as the value of x grows indefinitely.

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